A bar magnet having a magnetic moment of 2×105J/T is placed by the direction of uniform magnetic field of magnitude B=14×10−5T. The work done in rotating the magnet slowly through 600 from the direction of field is

θ1=00, θ2=600W=MBcosθ1−cosθ2 =MBcos00−cos600 =MB1−12=MB2=2×105×14×10−52=14J

A bar magnet having a magnetic moment of 2×105J/T is placed by the direction of uniform magnetic field of magnitude B=14×10−5T. The work done in rotating the magnet slowly through 600 from the direction of field is

θ1=00, θ2=600W=MBcosθ1−cosθ2 =MBcos00−cos600 =MB1−12=MB2=2×105×14×10−52=14J

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A bar magnet having a magnetic moment of $2 \times 10^{5} J / T$ is placed by the direction of uniform magnetic field of magnitude $B = 14 \times 10^{- 5} T .$ The work done in rotating the magnet slowly through $60^{0}$ from the direction of field is

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14 J

8.4 J

4 J

1.4 J

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$θ_{1} = 0^{0}$ , $θ_{2} = 60^{0}$

$W = M B (\cos θ_{1} - \cos θ_{2})$

$= M B [\cos 0^{0} - \cos 60^{0}]$

$= M B [1 - \frac{1}{2}]$

$= \frac{M B}{2} = \frac{2 \times 10^{5} \times 14 \times 10^{- 5}}{2} = 14 J$

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A bar magnet having a magnetic moment of 2×105J/T is placed by the direction of uniform magnetic field of magnitude B=14×10−5T. The work done in rotating the magnet slowly through 600 from the direction of field is

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A bar magnet having a magnetic moment of $2 \times 10^{5} J / T$ is placed by the direction of uniform magnetic field of magnitude $B = 14 \times 10^{- 5} T .$ The work done in rotating the magnet slowly through $60^{0}$ from the direction of field is