Q.

A bar magnet is at right angles to a uniform magnetic field. The couple acting on the magnet is to be one fourth by rotating it from the position. The angle of rotation is

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a

sin–1(0.25)

b

cos–1(0.25)

c

90°–sin–1(0.25)

d

90°–cos–1(0.25)

answer is B.

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Detailed Solution

τ=MBsin [ π2-θ] where θ is the angle of rotation .

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