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A bar magnet is oscillating in the Earth’s magnetic field with a period T. What happens to its period and motion if its mass is quadrupled?

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motion remains S.H.M with time period=2T

motion remains simple harmonic with time period = T/2

motion remains S.H.M and period remains neatly constant

motion remains S.H.M with time period=4T

answer is B.

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Detailed Solution

Time period of oscillation is given by $T = 2 π \sqrt{\frac{I}{MB}}$

$As, I \propto m$

Time period will be doubled.

hence, motion remains S.H.M with time period=2T

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