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A bar magnet M is allowed to fall towards a fixed conducting ring C with its plane horizontal. If ‘g’ is the acceleration due to gravity, ‘v’ is the velocity of the magnet at t =2s and ‘s’ is the distance travelled it in the same time then

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v > 2g

v > 4g

s > 2g

s < 2g

answer is D.

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Detailed Solution

$S < \frac{1}{2} {gt}^{2} \Rightarrow S < 2 g \Rightarrow V < gt$

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