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A bar magnet M is allowed to fall towards a fixed conducting ring C. If g is the acceleration due to gravity, v is the velocity of the magnet at $t = 2 s$ and $s$ is the distance travelled by it in the same time then:

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$s > 4 g$

$v < 4 g$

$v > 2 g$

$s > 2 g$

answer is B.

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Detailed Solution

$v = u + at = 2 a$

$s = \frac{1}{2} {at}^{2} = 2 a$

Using Lenz law we can say motion of magnet will be opposed, so $a < g$ .

Thus, $v < 2 g$ and $s < 2 g$ .

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