A bar magnet of length 0.1 m and with a magnetic moment of 5 Am² is placed in a uniform magnetic field of intensity 0.4T, with its axis making an angle of 60° with the field. What is the torque on the magnet ?

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Detailed Solution

$\begin{array}{l} τ = MBsin θ \Rightarrow τ = 5 \times 0 .4 \times \frac{\sqrt{3}}{2} \\ τ = \sqrt{3} = 1 .732 Nm \end{array}$

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