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A bar magnet of length 10cm and pole strength 20 A-m is deflected through $30^{o}$ from the magnetic meridian. If earth’s horizontal component field is $\frac{320}{4 π} A / m .$ The moment of the deflecting couple is

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$160 \times 10^{- 7} N m$

$320 π \times 10^{7} N m$

$320 \times 10^{- 7} N m$

answer is C.

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