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Q.

 A bar magnet of length 16 cm has a pole strength of 500 milli amp.m. The angle at which it should be placed to the direction of external magnetic field of induction 2.5 gauss so that it may experience a torque of 3×10−5Nm

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a

π

b

π / 2

c

π / 3

d

π/6

answer is C.

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Detailed Solution

τ=MBsin⁡θ

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 A bar magnet of length 16 cm has a pole strength of 500 milli amp.m. The angle at which it should be placed to the direction of external magnetic field of induction 2.5 gauss so that it may experience a torque of 3×10−5Nm