A bar magnet of length ' $l$ ' and magnetic dipole moment ' $M$ ' is bent in the form of an arc as shown in figure . The new magnetic dipole moment will be

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$\frac{3}{π} M$

$\frac{2}{π} M$

$\frac{M}{2}$

$M$

answer is A.

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Detailed Solution

Magnetic dipole moment
$M = m \times l M' = m \times r$
From figure
$l = \frac{π r}{3} o r r = \frac{3 l}{π}$
So, $M' = m \times r = \frac{m \times 3 l}{π} = \frac{3}{π} M$

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