A bar magnet of magnetic moment 10 Am2 has a cross sectional area of 2.5 × 10–4 m2. If the intensity of magnetization of the magnet is 106 A/m, then the length of magnet is

I=MV=MA.l ⇒l=MA.I=102.5×10-4×106=0.04m

I=MV=MA.l ⇒l=MA.I=102.5×10-4×106=0.04m

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A bar magnet of magnetic moment 10 Am² has a cross sectional area of 2.5 × 10^–4 m². If the intensity of magnetization of the magnet is 10⁶ A/m, then the length of magnet is

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0.4m

0.04cm

0.04m

40 cm

answer is C.

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$I = \frac{M}{V} = \frac{M}{A . l} \Rightarrow l = \frac{M}{A . I} = \frac{10}{2.5 \times 10^{- 4} \times 10^{6}} = 0.04 m$

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