A bar magnet of magnetic moment 2.0 A-m2 is placed in a uniform magnetic induction field of 8×10−5T. If each pole of the magnet experiences a force of 4×10−4N, the length of the magnet is :

F=mB⇒F=M2lB⇒4×10−4=22l×8×10−52l=0.4m

A bar magnet of magnetic moment 2.0 A-m2 is placed in a uniform magnetic induction field of 8×10−5T. If each pole of the magnet experiences a force of 4×10−4N, the length of the magnet is :

F=mB⇒F=M2lB⇒4×10−4=22l×8×10−52l=0.4m

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A bar magnet of magnetic moment 2.0 A-m² is placed in a uniform magnetic induction field of $8 \times 10^{- 5} T$ . If each pole of the magnet experiences a force of $4 \times 10^{- 4} N,$ the length of the magnet is :

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0.1m

0.3m

0.2m

0.4m

answer is D.

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$F = m B \Rightarrow F = \frac{M}{2 l} B$

$\Rightarrow 4 \times 10^{- 4} = \frac{2}{2 l} \times 8 \times 10^{- 5}$

$2 l = 0.4 m$

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A bar magnet of magnetic moment 2.0 A-m2 is placed in a uniform magnetic induction field of 8×10−5T. If each pole of the magnet experiences a force of 4×10−4N, the length of the magnet is :

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A bar magnet of magnetic moment 2.0 A-m² is placed in a uniform magnetic induction field of $8 \times 10^{- 5} T$ . If each pole of the magnet experiences a force of $4 \times 10^{- 4} N,$ the length of the magnet is :