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Q.

A bar magnet of magnetic moment M1 is suspended by a wire in a magnetic field. The tip of the wire is rotated through 180, then the magnet rotated through 45. Under similar condition, the magnet of magnetic moment M2 is rotated through 30, the ratio of M1 and M2 is

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a

1:2

b

1:2

c

2:1

d

2:1

answer is C.

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Detailed Solution

We know that T=MBSinθ

But T=Cϕ

Cϕ=MBSinθ

For first magnet

c(180)=M1BSin45________1

For second magnet

c(180)=M2BSin30________2

From 1 and 2

M1BSin45=M2BSin30

M1M2=12

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