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Q.

A bar magnet of magnetic moment M and moment of inertia I is freely suspended such that the magnetic axial line is in the direction of magnetic meridian. If the magnet is displaced by a very small angle θ, angular acceleration is (magnetic induction of earth's horizontal field is BH )

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a

IθMBH

b

MBHθI

c

IBHθM

d

MθIBH

answer is A.

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Detailed Solution

Restoring torque on the magnet, τ=-2mBHlsinθ=-MBHsinθ

if θ is small sinθ=θ⇒Iα=-MBHθ;α=MBHθI

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