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Q.

A bar magnet of moment of inertia $0.2 {kgm}^{2}$ is placed in uniform magnetic field of strength 0.2T. Magnetic moment of bar magnet is $10 {Am}^{2}$ if it displaces from equilibrium by small angle then time taken by it to reach one extreme to another extreme

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a

1 sec

b

2 sec

c

0.5 sec

d

$\frac{1}{4} \sec$

answer is A.

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Detailed Solution

One extreme another extreme point $T' = \frac{T}{2}$

$⇒T'= \frac{1}{2} (2 π \sqrt{\frac{I}{MB}}) = π \sqrt{\frac{0.2}{10 \times 0.2}} = 1 s$

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A bar magnet of moment of inertia 0.2kgm2 is placed in uniform magnetic field of strength 0.2T. Magnetic moment of bar magnet is 10 Am2 if it displaces from equilibrium by small angle then time taken by it to reach one extreme to another extreme