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Q.

A bar magnet of moment of inertia $9 \times 10^{- 5} k g m^{2}$ placed in a vibration magnetometer and oscillating in a uniform magnetic field $16 π^{2} \times 10^{- 5} T$ makes 20 oscillation in 15s. The magnetic moment of the bar magnet is

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a

$2 A m^{2}$

b

$3 A m^{2}$

c

$5 A m^{2}$

d

$4 A m^{2}$

answer is A.

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Detailed Solution

$T = 2 π \sqrt{\frac{I}{M B}} \to M = \frac{4 π^{2} I}{B T^{2}} = 4 A m^{2}$

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A bar magnet of moment of inertia 9×10−5kg m2 placed in a vibration magnetometer and oscillating in a uniform magnetic field 16π2×10−5T makes 20 oscillation in 15s. The magnetic moment of the bar magnet is