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Q.

A bar magnet with a magnetic moment 5Am2 is placed in parallel position relative to a magnetic field of 0.4 T. The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is 

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a

4 J 

b

1 J 

c

Zero 

d

2 J  

answer is B.

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Detailed Solution

w=MB(cosθ1−cosθ2)=5×0.4(cos0−cos180)=4 J

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