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A bar of iron is 10 cm at 20°C. At 19°C it will be (α of iron =11X 10^-6/°C)

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11 X 10^-6 cm Shorter

11 X 10^-6 cm longer

11 X 10^-5 cm longer

11 X 10^-5 cm Shorter

answer is B.

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Detailed Solution

$∆ l = l_{2} - l_{1} = l_{1} α ∆ T$

$\Rightarrow ∆ l = 10 \times 11 \times 10^{- 6} \times (- 1^{0}) = - 11 \times 10^{- 5} c m$

Therefore, 11 X 10^-5 cm Shorter

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