A basic buffer contains equal concentration of base and its salt. The dissociation constant of base is ${10}^{-6}$. Then the $\mathrm{pH}$ of the buffer solution is

The pH of the solution can be calculated as:

$pH=14-p^{K_b}-\log \left[\frac{Base}{Salt}\right]$

Since, the amount of the Base and salt is same, it will cancel out. Putting the values, we get:

$pH=14-6-\log 1$

$pH=14-6-0$

$pH=14-6$

$pH=8$

Therefore, the correct option is (B).