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Q.

A bat can hear sound of frequencies up to 120 kHz. Determine the minimum wavelength of sound which it can hear. Take speed of sound in air to be 344ms-1   

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a

3.87×10-3m

b

2.87×10-3m

c

2.0×10-2m

d

4.87×10-6m

answer is C.

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Detailed Solution

Given, f=120kHz=120×103Hz,V=344ms1  From relation V=  Wavelength λ=Vf=544120×103 =2.87×103m( or 2.87) i.e., the bat can hear sound of minimum wavelength 2.87 mm

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