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Q.

A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12 ms-1.If the mass of the ball is 0.15 kg, the impulse imparted to the ball is

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a

10.2 Ns

b

1.5 Ns

c

7.2 Ns

d

3.6 Ns

answer is B.

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Detailed Solution

 Change in momentum =mΔv
Given,m = 0.15 kg,
Δp=0.15×12-(-0.15×12)
Δp=3.6 N s
In the direction from the batsman to the bowler.

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