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A battery is charged at a potential of 15 V for 8 hours when the current flowing is 10 A. The battery on discharge supplies a current of 5 A for 15 hours. The mean terminal voltage during discharge is 14 V. The “watt-hour” efficiency of the battery is

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answer is A.

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$η = \frac{o u t p u t}{i n p u t}$

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