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Q.

A battery is supplying power to a tape recorder by cable of resistance of $0.02 Ω .$ If the battery is generating 50 W power at 5 V, then the power received by the tape recorder is

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a

50 W

b

45 W

c

30 W

d

48 W

answer is D.

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Detailed Solution

$P = V I o r 50 = 5 \times I o r I = 10 A$

Power lost in cable $= I^{2} R = 10 \times 10 \times 0.2 = 2 W$

Power supplied to the tap recorder $= 50 W - 2 W = 48 W$

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