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Q.

A battery of 9v is connected in series with resistors of 0.2 Ω,0.3 Ω,0.4 Ω,0.5 Ω and 12 Ω respectively. How much current would flow through the 12 Ω resistor?


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a

0.5A 

b

0.75A

c

0.67A

d

0.45A 

answer is C.

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Detailed Solution

Current flowing in the circuit can be found by using Ohm’s Law,
   V=I×R
Combined resistance, R = 0.2+0.3+0.4+0.5+12 = 13.4 Ω
Potential difference , V = 9 V (given)
Hence , 9 = I×13.4
 Current , I = 913.4
      I  = 0.67 A.
 
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