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A battery of e.m.f. 10 V is connected to resistance as shown in figure. The potential difference $V_{A} - V_{B}$ the points A and B is

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2 V

$\frac{20}{11} V$

$- 2 V$

5 V

answer is B.

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Detailed Solution

$R_{eq} = 5 Ω, Current i = \frac{10}{5} = 2 A$ and current in each branch = 1 A

Potential difference between C and A,

$V_{C} - V_{A} = 1 \times 1 = 1 V$ …..(i)

Potential difference between C and B,

$V_{C} - V_{B} = 1 \times 3 = 3 V$ …..(ii)

On solving (i) and (ii), $V_{A} - V_{B} = 2 V$

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