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Q.

A battery of emf 10V and internal resistance 3Ω is connected to a resistor. If the current in the circuit is 0.5A, what is the resistance of the resistor ? What is the terminal voltage of the battery when the circuit is closed ?

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Detailed Solution

E=10V,r=3Ω,I=0.5A
Let ‘R’ be the resistance of the resistor
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I=ER+r R=EI−r=100.5−3=17Ω
Terminal voltage of battery
V=E−Ir=10−0.5×3=8.5V

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