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Q.

A battery of emf 10V and internal resistance $3 Ω$ is connected to a resistor. The current in the circuit is 0.5A. then the terminal voltage of the battery when the circuit is close is ______ volts.

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answer is 8.5.

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Detailed Solution

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$i = \frac{E}{R + r}; \Rightarrow R + r = \frac{10}{0.5} \Rightarrow R = 20 - 3 = 17 Ω V = iR = (0.5) (17) = 8.5 V$ sub

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