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A battery of emf $E_{0} = 5 V$ and internal resistance $5 Ω$ is connected across a long uniform AB of length 1 m and resistance per unit length $5 Ω m^{- 1}$ . Two cells of $E_{1} = 1 V$ and $E_{2} = 2 V$ are connected as shown in the figure.

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The null point is at $A$

The null point is at distance of $\frac{8}{15}$ m from $A$

If jockey is touched to point $B$ the current in the galvanometer will be going towards $B$

When jockey is connected to point $A$ no current is flowing through $1 V$ battery.

answer is B, C.

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Detailed Solution

The effective $e m f$ the two cells in parallel is

$e = \frac{1 \times 2 - 2 \times 1}{1 + 2} = 0$

So null point will be at zero distance from $A$ . When jockey istouched to $B,$ the current flows through $2 V$ cell towards $B$ .

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