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Q.

A battery of internal resistance 2   Ω is connected to a variabte resistor whose value can vary from 4   Ω  to   10   Ω. The resistance is initially set at 4   Ω.  If the resistance is now increased, then

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a

power consumed by it will decrease

b

power consumed by it will increase

c

power consumed by it may increase or may decrease

d

power consumed by it will first increase then decrease

answer is A.

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Detailed Solution

P=I2R=VR2=ε2R+r2R

ε is constant and (R + r) increases rapidly, then P .

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