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Q.

A battery of negligible internal resistance is connected with 10m long wire. A standard cell gets balanced on 6m length of this wire. On increasing the length of potentiometer wire by 2m, the null point with the same standard cell in the secondary will be (no series resistance in primary)

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a

increased by 2m

b

decreased by 2m

c

increased by 1.2m

d

decreased by 1.2m

answer is C.

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Detailed Solution

$E^{'} = \frac{E \times R_{P} \times l}{(r + R_{s} + R_{p}) L}$
All are constant except l and L
$∴ lαL; \frac{l_{1}}{l_{2}} = \frac{L_{1}}{L_{2}}; \frac{6}{l_{2}} = \frac{10}{12} ∴ l_{2} = 7 .2 m$
$∴$ increase in length ; $Δl = (l_{2} - l_{1}) = 1 .2 m$

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A battery of negligible internal resistance is connected with 10m long wire. A standard cell gets balanced on 6m length of this wire. On increasing the length of potentiometer wire by 2m, the null point with the same standard cell in the secondary will be (no series resistance in primary)