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Q.

A beaker containing water is placed on the platform of a spring balance. The balance reads 1.5 kg. A stone of mass 0.5 kg and density 104 kg/m3 is immersed in water without touching the walls of the beaker. What will be the balance reading now?

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a

2kg

b

2.5kg

c

1 kg

d

3 kg

answer is A.

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Detailed Solution

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As the water exerts upthrust on the stone, the stone also exerts the same force on water, according to Newton's third law. 

Upthrust force acting on the stone is

U=Vstone ρωg=mstone ρstone ρωg=0.5104×1000×10=0.5N

Also, the weight is exerted on the beaker. Therefore the reading will be 1.5 + 0.5 = 2kg.

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A beaker containing water is placed on the platform of a spring balance. The balance reads 1.5 kg. A stone of mass 0.5 kg and density 104 kg/m3 is immersed in water without touching the walls of the beaker. What will be the balance reading now?