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Q.

A beaker of depth 20cm is half filled with a liquid of refractive index 1.4 and half filled with a liquid of refractive index 1.7. What is the apparent depth of a coin lying at the bottom of the beaker, assuming that liquids do not mix with each other?

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a

$\approx 13 c m$

b

7.1 cm

c

9 cm

d

$\approx 11 c m$

answer is A.

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Detailed Solution

Apparent depth =
$d_{a p} = \frac{d_{1}}{μ_{1}} + \frac{d_{2}}{μ_{2}} = \frac{10}{1.7} + \frac{10}{1.4} ≃ 13 c m$

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