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Q.

A beam of light of wavelength  500 nm  from a distant source falls on a single slit 2.00 mm wide and the resulting diffraction pattern is observed on a screen 4 m  away.  Then distance between the first dark fringes on either side of the central fringe is

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a

2.4  mm

b

1.2  mm

c

3.6  mm

d

2  mm

answer is B.

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Detailed Solution

Wavelength λ=500 nm=500×10−9 m

Source distance a=2 mm=2×10−3 m

Distance of the screen D=4 m

    β=λDa

      =5×10−7×42×10−3=1mm

∴  y=2β=2 mm

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