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A beam of electrons is accelerated through a potential difference V. It is then passed normally through a uniform magnetic field where it moves in a circle of radius r. It would have moved in a circle of radius 2r, if it were initially accelerated through a potential difference of

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$\sqrt{2} V$

$2 \sqrt{2} V$

answer is D.

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Detailed Solution

$r = \frac{\sqrt{2 qVm}}{Bq} or r \propto \sqrt{V}$
Where, = V = potential difference

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