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Q.

A beam of light consisting of two wavelengths, 650 nm and 520 nm is used to obtain interference in YDSE. If bright fringes due to both the wavelengths coincide at any point P then least distance of P from central maxima is (Slit separation is 2 mm and distance between slits and screen is 1.2 m)

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a

1.8 mm

b

1.56 mm

c

3 mm

d

2.36 mm

answer is A.

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Detailed Solution

$when two maxima of different colour coincide condition is {nλ}_{1} = (n + 1) λ_{2} n 650 = (n + 1) 520 solving n = 4 so 4 th maxima of 650 nm and 5 th maxima of 520 nm coincide Their distance from central maxima is 4 β_{1} or 5 β_{2} [β = \frac{λD}{d}] = \frac{5 x 520 x 10^{- 9} x 1.2}{2 x 10^{- 3}} m = 1.56 mm$

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