A beam of light from a source L is inclined normally on a plane mirror fixed at a certain distance ‘x’ from the source the beam is reflected back as a spot on a scale placed just above the source L. When the mirror is rotated through a small angle $θ$ , the spot of the light is found to move through a distance ‘y’ on the scale. The angle $θ$ is given by

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$\frac{y}{2 x}$

$\frac{x}{2 y}$

$\frac{y}{x}$

$\frac{x}{y}$

answer is A.

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Detailed Solution

$\begin{array}{l} 2 θ = \frac{y}{x} \\ θ = \frac{y}{2 x} \\ 2 θ \approx \sin θ \end{array}$

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