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Q.

A beam of light is converging towards a point l on a screen. A plane glass plate of thickness 't' in the direction of the beam of refractive index $μ$ , is introduced in the path of the beam. The convergence point is shifted by

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a

$t (1 - \frac{1}{μ}) nearer$

b

$t (1 + \frac{1}{μ}) nearer$

c

$t (1 + \frac{1}{μ}) away$

d

$t (1 - \frac{1}{μ}) away$

answer is A.

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Detailed Solution

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shift $∆ x = (1 - \frac{1}{μ}) t$ and shift takes place in direction of ray.

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A beam of light is converging towards a point l on a screen. A plane glass plate of thickness 't' in the direction of the beam of refractive index μ, is introduced in the path of the beam. The convergence point is shifted by