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A beam of light propagating in medium A with index of refraction n (A) passes across an interface into medium B with index of refraction n (B). The angle of incidence is greater than the anlgle of refraction; v(A) and v(B) denote the speed of light in A and B. Then which of the following is true?

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v(A) > v(B)and n(A) > n(B)

v(A) > v(B) and n(A) < n (B)

v(A) < v(B) and n(A) > n(B)

v(A) < v (B) and n(A) < n (B)

answer is C.

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Detailed Solution

given that angle of incidence is greater than angle of refraction it means that the light ray is going from rarer medium to denser medium hence

$V_{A} > V_{B} a n d r e f r a c t i v e i n d e x n = \frac{V_{0}}{V}; n \propto \frac{1}{V} h e n c e V_{A} > V_{B} a n d n_{A} < n_{B}$

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