Q.

A beam of protons with speed  4×105ms1 enters a uniform magnetic field of 0.3T at an angle of 60º to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton  1.67×1027kg,  charge of the proton 1.69×1019 C)

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a

2cm

b

5cm

c

4cm

d

12cm

answer is B.

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Detailed Solution

pitch=Vcosθ.T=Vcosθ×2πmqBpitch=4×105×cos60º×2π×1.67×10271.69×1019×0.3pitch=1.67×4π1.69×0.3×103m4cm

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A beam of protons with speed  4×105ms−1 enters a uniform magnetic field of 0.3T at an angle of 60º to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton  1.67×10−27kg,  charge of the proton 1.69×10−19 C)