(A) Benzoyl peroxide can initiate free radical polymerisation.
(R) Phenyl free radical is very stable.

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Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true but (R) is not the correct explanation of (A)

(A) is true but (R) is false

Both (A) and (R) are false

answer is C.

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Detailed Solution

Statement (A) is true, while statement (R) is false.

(A) Benzoyl peroxide is a common initiator for free radical polymerization. When benzoyl peroxide is heated, it decomposes into two benzoyloxy free radicals, which are highly reactive and can initiate the polymerization reaction by attacking the double bond of a monomer molecule. This reaction results in the formation of a new free radical on the monomer, which can then react with another monomer to form a growing polymer chain.

(R) Phenyl free radical is not very stable. Free radicals are highly reactive species and are generally unstable due to their unpaired electron. Phenyl free radical, which is formed by homolytic cleavage of a carbon-carbon bond in a phenyl group, is no exception. Phenyl free radicals are highly reactive and can undergo various reactions such as addition or abstraction reactions to form new products. They are not considered to be very stable compared to some other free radicals such as the tert-butyl free radical.

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