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Q.

A biased die is marked with numbers 2,4,8,16, 32,32 on its faces and the probability of getting a face with mark n is 1n. If the die is thrown thrice, then the probability, that the sum of the numbers obtained is 48 , is

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a

 3210

b

 7212

c

 13212

d

 7211

answer is D.

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Detailed Solution

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P(n)=1n P(2)=12       P(8)=18 P(4)=14       P(16)=116 P(32)=232

Possible cases

16,16,16 and 32,8,8

Probability = 1163+232×18×18×3=13163

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