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A bicycle wheel of radius 0.4 m has 20 spokes. It is rotating at the rate of 180 revolutions per minute, perpendicular to the horizontal component of earth’s magnetic field of 0.4 x10^-4 T. The emf induced between the rim and the axle of wheel will be nearly

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6x10^-5 V

12x10^-5 V

6x10^-6 v

12x10^-6 v

answer is A.

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Detailed Solution

$ε = \frac{1}{2} {Bl}^{2} w$
$= \frac{1}{2} \times 4 \times 10^{- 5} \times 16 \times 10^{- 2} \times \frac{2 π \times 180}{60}$

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