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A big drop of water has volume $1 mL$ . How many molecules of water are there in this drop, if the density of water is $1 g / mL$ ?

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3.22 \times 1 0^{24}

3.88 \times 1 0^{26}

3.39 \times 1 0^{29}

3.34 \times 1 0^{22}

answer is D.

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Detailed Solution

The number of molecules of water in a drop of water are

3.34 \times 1 0^{22}

Volume of drop of water

= 1 mL

Mass of drop of water

= 1 g

Molecular mass of water

, H_{2} O = 2 \times 1 + 16

\Rightarrow

= 18 u

Gram molecular mass of water

= 18 g / mol

18

grams of water contains

= 6.022 \times 1 0^{23}

molecules
1 g of water contains

= \frac{6.022 \times 1 0^{23}}{18}

\Rightarrow

3.34 \times 1 0^{22}

molecules

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