A big irregular shaped vessel contained water, conductivity of which was 2.56 x 10^-3S^-1m^-1. 585 g of NaCl was then added to the water and conductivity after the addition of NaCl, was found to be 3.06 x 10^-3S^-1m^-1. The molar conductivity of NaCl at this concentration is 1.5 x 10^-2S^-1m²mol^-1. The capacity of vessel if it is fulfilled with water, is

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3 x 10⁴L

3 x 10⁵ L

3 x 10⁸ L

30 L

answer is D.

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Detailed Solution

$\begin{array}{l} \land_{m} = \frac{k}{c} \Rightarrow 1.5 \times 10^{- 2} = \frac{3.06 \times 10^{- 3} - 2.56 \times 10^{- 3}}{c} \\ ∴ c = \frac{1}{30} mol / m^{3} = \frac{1}{30} \times 10^{- 3} {molL}^{- 1} = \frac{585 / 58.5}{v} \end{array}$
v = 3 x 10⁵ L

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