A bird flies for 4 s with a velocity of $\left|t-2\right|m{s}^{-1}$ in a straight line, where t = time in second. It covers a distance of

Since, v = (t-2), so  On plotting a graph between v and t , we get a straight line AB and BC as shown in figure (below).

The distance covered in 4 s is equal to the area under the velocity- time graph = Area of $\Delta AOB+Area of \Delta ABCD$

$=\frac{2\times 2}{2}+\frac{2\times 2}{2}=2+2=4 m$