A bird in air looks at a fish vertically below it and inside water; h₁ is the height of the bird above the surface of water and h₂ the depth of the fish below the surface of water. If refractive index of water with respect to air be $μ$ , then the distance of the fish as observed by the bird is :

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$h_{1} + h_{2}$

$h_{1} + \frac{h_{2}}{μ}$

$μ h_{1} + h_{2}$

$μ h_{1} + μ h_{2}$

answer is B.

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Detailed Solution

Given, h₁ is the height of the bird above surface and h₂ is the depth of the fish below surface.

And $μ$ is the refractive index of the water.

$μ = \frac{Re a l d e p t h}{A p p d e p t h}$

Real depth is $h_{1} + \frac{h_{2}}{μ}$ as seen by the bird.

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