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A bird is flying with a velocity v between two long vertical plane mirrors making an angle $θ$ with mirror M₁ as shown. Then what will be the relative velocity of approach between the images formed by the mirrors due to the 1st reflection in each of them

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$ν sin θ$

$2 (ν sin θ +L)$

Zero

$2 ν sin θ$

answer is D.

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Detailed Solution

The image velocity by both the mirror is equal hence the velocity of approach will be zero

$ν_{I_{1} I_{2}} = ν_{I_{2}} - ν_{I_{1}} = 0$

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