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Q.

A bird is flying with a velocity v between two long vertical plane mirrors making an angle θ with mirror M1 as shown. Then what will be the relative velocity of approach between the images formed by the mirrors due to the 1st reflection in each of them

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a

ν sin θ

b

2ν sin θ

c

2(ν sin θ+L)

d

Zero

answer is D.

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Detailed Solution

The image velocity by both the mirror is equal hence the velocity of approach will be zero

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νI1I2=νI2νI1=0

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