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Q.

A bird is perched on the top of a tree 20 mts high and its elevation from the point on the ground is 45° . It flies off horizontally straight away from the observer and in one second the elevation of the bird is reduced to  30°. Then Two times of speed of bird is λ m/s then λ is________  (where . represents G.I.F)

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answer is 29.

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Detailed Solution

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tan45o=1  so height =distance of pole from O=20  Let Bird travels distance x horizontally. tan30=2020+x=1320+x=203x=20320x=20(31) so speed = distance  time =x1sec  Speed is 20(31)m/sec

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