A bivalent metal has 12 equivalent weight. The molecular weight of its oxide is

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answer is C.

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Detailed Solution

$E q u i v a l e n t w e i g h t = \frac{M o l e c u l a r w e i g h t}{n - f a c t o r}$

So, Molecular weight= equivalent weight x n-factor

Since it is a bivalent metal therefore it’s n-factor=2.

So, Atomic weight=12 $\times$ 2=24

Since it is bivalent ion it needs only one oxygen atom to form an oxide.

Molecular weight of the oxide = Atomic weight of metal+ Atomic weight of oxygen.

Therefore molecular weight of the oxide = 24+16=40.

Hence the correct option is (C).

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