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A black body at temperature T = 400K is emitting radiations at rate $200 W / m^{2} .$ Another body of surface area $2 m^{2}$ coefficient of reflectivity (r) = 0.3 and zero coefficient of transmission is at temperature 800 K. The correct statement(s) about the another body is

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emissivity is 0.7

Emissive power is 2240 $W / m^{2}$

Power emitted is 2240 W

Power emitted is 4480 W

answer is A, C, D.

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Detailed Solution

$200 = σ .1. {(400)}^{4}$

$Power emitted by the other body ...... (i)$

$P = σ \times 0.7 \times 2 \times {(800)}^{4} ...................... (i i)$

$\Rightarrow \frac{P}{200} = 0.7 \times 2 \times 2^{4} \Rightarrow P = 200 \times 2 \times 2^{4} .$

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