A black body is at temperature of 2880 K. The energy of radiation emitted by thisobject between wavelength 4990 A∘ and 5000 A∘ is U1, between 9990 A° and 10000 A∘ is U2, and between 14990 A∘ and 15000 A∘ is U3. The Wein's constant is b = 2.88 × 10-3mK then :

λmT=b λm=10,000 A∘So, U2 is maximum which is the area under dEdλ vsλ curve at λ=10,000 A∘

A black body is at temperature of 2880 K. The energy of radiation emitted by thisobject between wavelength 4990 A∘ and 5000 A∘ is U1, between 9990 A° and 10000 A∘ is U2, and between 14990 A∘ and 15000 A∘ is U3. The Wein's constant is b = 2.88 × 10-3mK then :

λmT=b λm=10,000 A∘So, U2 is maximum which is the area under dEdλ vsλ curve at λ=10,000 A∘

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A black body is at temperature of $2880 K .$ The energy of radiation emitted by this
object between wavelength $4990 \overset{\circ}{A}$ and $5000 \overset{\circ}{A}$ is $U_{1},$ between $9990 \overset{°}{A}$ and $10000 \overset{\circ}{A}$ is $U_{2},$ and between $14990 \overset{\circ}{A}$ and $15000 \overset{\circ}{A}$ is $U_{3} .$ The Wein's constant is $b = 2.88 \times 10^{- 3} m K$ then :

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$U_{1} < U_{2} < U_{3}$

$U_{1} = U_{3} < U_{2}$

$U_{2} > U_{3}$

$U_{2} > U_{1}$

answer is A, B.

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$λ_{m} T = b λ_{m} = 10, 000 \overset{\circ}{A}$

So, $U_{2}$ is maximum which is the area under $\frac{d E}{d λ} v_{s} λ$ curve at $λ = 10, 000 \overset{\circ}{A}$

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A black body is at temperature of 2880 K. The energy of radiation emitted by thisobject between wavelength 4990 A∘ and 5000 A∘ is U1, between 9990 A° and 10000 A∘ is U2, and between 14990 A∘ and 15000 A∘ is U3. The Wein's constant is b = 2.88 × 10-3mK then :

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